【单选题】【消耗次数:1】
设有向图D = áV, E?, 其中 V={v1, v2, v3, v4, v5}, E={áv4, v1?, áv1, v1?,áv1, v2?,áv1, v3?, áv3, v1?, áv5, v3?},则v1的邻域 N(v1) =
{v3, v4};
{v2, v3,v4};
{v1, v2, v3, v4};
{v2,v3}。
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相关题目
【单选题】 设有向图D = áV, E?, 其中 V={v1, v2, v3, v4, v5}, E={áv4, v1?, áv1, v1?,áv1, v2?,áv1, v3?, áv3, v1?, áv5, v3?},则v1的闭邻域 N(v1) =
①  {v3, v4};
②  {v2, v3,v4};
③  {v1, v2, v3, v4};
④  {v2,v3}。
【单选题】 设无向图G1 = áV1, E1?, 其中, V1 = {v1, v2, v3, v4, v5}, E1 = {(v1, v2), (v2, v3), (v3, v4), (v3, v3), (v4, v5)},则v2的邻域 N(v2)为:
①  {v1, v2, v3};
②  {v1, v3};
③  {v1, v2, v3, v4, v5};
④  {v2}。
【单选题】 设有向图D = áV, E?, 其中 V={v1, v2, v3, v4, v5}, E={áv4, v1?, áv1, v1?,áv1, v2?,áv1, v3?, áv3, v1?, áv5, v3?},则v1的先驱元集G -(v1) =
①  {v3, v4};
②  {v1, v3,v4};
③  {v1, v2, v3, v4};
④  {v2,v3}。
【单选题】 设有向图D = áV, E?, 其中 V={v1, v2, v3, v4, v5}, E={áv4, v1?, áv1, v1?,áv1, v2?,áv1, v3?, áv3, v1?, áv5, v3?},则v1的后继元集G +(v1) =
①  {v3, v4};
②  {v1, v3,v4};
③  {v1, v2, v3, v4};
④  {v2,v3}。
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①  {v1, v2, v3};
②  {v1, v3};
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【单选题】 运行以下程序,从键盘上输入china# #includevoid main() { int v1=0,v2=0; char ch; while((ch=getchar())!=#) switch(ch) { case a: case h: default: v1++; case 0:v2++; } printf(%d,%d\n,v1,v2); } 运行结果( )。
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