【单选题】【消耗次数:1】
图示刚体在一个平面汇交力系作用下处于平衡,以下四组平衡方程中哪一组是不独立的<img src=https://huaweicloudobs.ahjxjy.cn/07088274D15325232B14A583B58DA6B7.png title=QQ截图20190715141952.png alt=QQ截图20190715141952.png/>
SmA(F) = 0, SmB(F) = 0;
SX = 0,SY = 0;
SX = 0,SmA(F) = 0;
SmA(F) = 0,SmC(F) = 0。
参考答案:
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相关题目
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①  SX = 0, Sx = 0, SmA(F) = 0;
②  SmO(F) = 0,SmA(F) = 0,SmB(F) = 0;
③  SmO(F) = 0,SmC(F) = 0,SY = 0;
④  SX = 0,SY = 0,SmO(F) = 0。
【单选题】 图示刚体在一个平面任意力系作用下处于平衡,以下四组平衡方程中哪一组是不独立的<img src=https://huaweicloudobs.ahjxjy.cn/06BB3A04A730753D2E54272845D85329.png title=QQ截图20190715141952.png alt=QQ截图20190715141952.png/>
①  SX = 0, SmO(F) = 0, SmA(F) = 0;
②  SmO(F) = 0,SmA(F) = 0,SmB(F) = 0;
③  SmA(F) = 0,SmC(F) = 0,SY = 0;
④  SX = 0,SmA(F) = 0,SmB(F) = 0。
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①  SY = 0, SmO(F) = 0;
②  SX = 0,SmO(F) = 0;
③  SX’ = 0,SmO(F) = 0;
④  SmO(F) = 0,SmA(F) = 0。
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