【判断题】【消耗次数:1】
方程个数等于未知量个数的线性方程组一定有唯一解.
正确
错误
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相关题目
【判断题】 方程个数小于未知量个数的线性方程组一定有解.
①  正确
②  错误
【判断题】 方程个数大于未知量个数的线性方程组一定有无穷多解.
①  正确
②  错误
【判断题】 若线性方程组AX=B中方程的个数等于未知量的个数,则AX=B有唯一解。
①  正确
②  错误
【判断题】 若线性方程组AX= B中,方程的个数小于未知量的个数,则AX=B一定有无穷多解。
①  正确
②  错误
【判断题】 若线性方程组AX=B的方程的个数大于未知量的个数,则AX=B一定无解。
①  正确
②  错误
【判断题】 若某个线性方程组相应的齐次线性方程组只有零解,则该线性方程组有唯一解。
①  正确
②  错误
【判断题】 方程的个数大于未知数的个数的齐次线性方程组必没有非零解
①  正确
②  错误
【单选题】 个未知量的齐次线性方程组有非零解的充分必要条件是()
①  方程个数
②  方程个数
③  方程个数
【判断题】 齐次线性方程组一定有解.
①  正确
②  错误
【判断题】 方程个数等于未知数个数的齐次线性方程组,有非零解得充要条件是系数矩阵的行列式等于零
①  正确
②  错误
随机题目
【单选题】 Most importantly, such an experience helps ____ a heightened sensitivity to other cultures and will bring about a greater appreciation of one’s own culture as well.
①  coach
②  forsake
③  foster
④  censor
【单选题】 She didn’ t come to the party last Sunday._____, she must have made the party more exciting.
①  If she came
②  Would she come
③  Had she come Did she come
【单选题】 Some companies have introduced flexible working time with less emphasis on pressure ____.
①  than more on efficiency
②  and more on efficiency
③  and more efficiency
④  than efficiency
【单选题】 Tom ____ his new job with confidence.
①  set out
②  set off
③  set up
④  set about
【单选题】 In some cases, your instructor may tell you the topics ____ or may give you a choice of topics to write about.
①  in advance
②  ahead of
③  above al
④  right away
【单选题】 Nancy was surprised that they have ____. They seemed to be a happy couple.
①  split up
②  broken down
③  fallen through
④  knocked out
【单选题】 — Whichsongdoyoulikebetter,Lucy?— IpreferthesongLittleApple ______ canattractmanypeople.
①  which
②  who
③  whom
④  where
【单选题】 Once ____, this power station will supply all the neighboring towns and villages with electricity.
①  it being completed
②  it completed
③  completed
④  it completes
【单选题】 The Brownings have not ____ yet and I doubt whether they will come.
①  turned in
②  turned out
③  turned up
④  turned to
【单选题】 The ____ in Janet’s character has hindered her from advancement in her career.
①  weakness
②  merit
③  defect
④  shortcoming