【单选题】【消耗次数：1】
A talk on developments in science and technology_______in the school hall next week.
①
given
②
will be given
③
has been given
④
give
参考答案：
复制
纠错
相关题目
【单选题】
The residents, _____had been damaged by the fire, were given help by the Red Cross.
①
all of their homes
②
all their homes
③
whose all homes
④
all of whose homes
【单选题】
The residents, _____had been damaged by the fire, were given help by the Red Cross.
①
all of their homes
②
all their homes
③
whose all homes
④
all of whose homes
【单选题】
The new technology has been ( ) in the industrial production.
①
utilized
②
possessed
③
elevated
④
focused
【填空题】
Direction: Fill in the blanks with the phrases given below. Change the form if necessary.[have access to; go off; desperate for; put up with; always the case; give advice; concentrate on; arrive at; make an effort; come in handy]5.Ill have to[填空1]the noise till I move next week.
【单选题】
33.Modern science and technology has _____ communication between people far apart.
①
madeconvenient
②
madeitconvenient
③
madeitconvenientfor
④
madeitconvenientto
【简答题】
Direction: Fill in the blank with the correct form of the word given.2. One has to be especially careful under such[填空1](circumstance).
【单选题】
The game was fixed for today but it has been____ for a week.
①
transfered
②
delayed
③
translated
④
postponed
【单选题】
This technology has been ?around for a long time, but not until recent years _______ it in marketing.
①
businesses employed
②
did businesses employ
③
businesses had employed?
④
had businesses employed
随机题目
【单选题】
在创建派生类对象时，构造函数的执行顺序是（）
①
对象成员构造函数―基类构造函数―派生类本身的构造函数
②
派生类本身的构造函数―基类构造函数―对象成员构造函数
③
基类构造函数―派生类本身的构造函数―对象成员构造函数
④
基类构造函数―对象成员构造函数―派生类本身的构造函数
【单选题】
如果某函数的返回值是个对象，则该函数被调用时，返回的对象（）。
①
是通过复制构造函数初始化的
②
是通过无参构造函数初始化的
③
用哪个构造函数初始化取决于函数的return语句是怎么写的
④
不需要初始化
【单选题】
假定一个类的构造函数为A（int aa，int bb） {a=aa--；b=a*bb；}，则执行A x（4，5）；语句后 ，x.a和x.b的值分别为（）
①
3和15
②
5和4
③
4和20
④
20和5
【单选题】
下列数组定义语句中，不合法的是（）
①
int a[3]={0，1，2，3}；
②
int a[]={0，1，2}；
③
int a[3]={0，1}；
④
int a[3]={0}；
【单选题】
以下正确的函数原型为（）
①
fun1（int x；int y）；
②
void fun1（x，y）；
③
void fun1（int x，y）；
④
void fun1（int，int）；