【简答题】【消耗次数:1】
在补码加减法运算中,采用双符号位的方法(变形补码)怎样进行溢出判断?
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相关题目
【简答题】 在补码加减法运算中,采用双符号位的方法(变形补码)怎样进行溢出判断?
【判断题】 补码加减法中,操作数用补码表示,两数相加减,符号位单独处理,减法用加法代替
①  正确
②  错误
【判断题】 使用变形补码运算可以避免溢出。
①  正确
②  错误
【单选题】 若整数的加减法指令的执行结果发生溢出则影响( )位。
①  SM1.3
②  SM1.0
③  SM1.1
④  SM1.2
【判断题】 两补码相加,采用1位符号位,当最高位有进位时表示结果产生溢出
①  正确
②  错误
【单选题】 为了便于检查加减运算是否发生溢出,定点运算器采用双符号位的数值表示,在寄存器和主存中是采用()的数值表示
①  双符号位
②  单符号位
③  上述两种方式
④  无符号位
【单选题】 两个补码数相减,在符号位相同时不会产生溢出,符号位不同时()产生溢出
①  有可能
②  没有可能
③  一定会
④  一定不会
【单选题】 在定点运算器中,无论采用双符号位还是采用单符号位,必须要有溢出判断电路,它一般用()来实现
①  与非门
②  或非门
③  异或门
④  与或非门
【单选题】 两个补码数相加,在符号位相同时有可能产生溢出,符号位不同时()
①  一定不会产生溢出
②  会产生溢出
③  也有可能产生滋出
④  不一定会产生擞出
【判断题】 原码和补码均可实现将减法运算转化为加法运算。
①  正确
②  错误
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